(3x+4)(x^2+x-2)=0

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Solution for (3x+4)(x^2+x-2)=0 equation: 


Simplifying
(3x + 4)(x2 + x + -2) = 0

Reorder the terms:
(4 + 3x)(x2 + x + -2) = 0

Reorder the terms:
(4 + 3x)(-2 + x + x2) = 0

Multiply (4 + 3x) * (-2 + x + x2)
(4(-2 + x + x2) + 3x * (-2 + x + x2)) = 0
((-2 * 4 + x * 4 + x2 * 4) + 3x * (-2 + x + x2)) = 0
((-8 + 4x + 4x2) + 3x * (-2 + x + x2)) = 0
(-8 + 4x + 4x2 + (-2 * 3x + x * 3x + x2 * 3x)) = 0
(-8 + 4x + 4x2 + (-6x + 3x2 + 3x3)) = 0

Reorder the terms:
(-8 + 4x + -6x + 4x2 + 3x2 + 3x3) = 0

Combine like terms: 4x + -6x = -2x
(-8 + -2x + 4x2 + 3x2 + 3x3) = 0

Combine like terms: 4x2 + 3x2 = 7x2
(-8 + -2x + 7x2 + 3x3) = 0

Solving
-8 + -2x + 7x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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